$\int\left(\left(x^2-2x+4\right)^5\left(2x-2\right)\right)dx$
$\left(x^2\left(\frac{1}{x}\right)\right)^{10}$
$10\cdot24^{\frac{1}{2}}$
$\frac{dt}{dy}y=\left(t\right)\left(t+8\right)\left(t+9\right)$
$\frac{a^p}{a^q}$
$du=\frac{27}{4}x^2dx$
$\frac{dy}{dt}=1-t+4y$
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