$3\cdot1^2+1$
$\frac{dy}{dx}=kqe^{-kx}$
$\frac{dy}{dx}=\frac{3x+2}{2x^2-1}$
$-248-185$
$\frac{d}{dx}9x^3\:+\:9y^3\:=\:3$
$\int3t\sin\left(2t\right)dt$
$\frac{-7-x}{-4}$
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