$6+7\left(3+5z\right)$
$2x+1\:+\:2x-1\:area$
$-\left(-35+18-\left(-7\right)+47-\left(-20\right)\right)$
$\frac{6^2}{3}$
$\int_{-\infty}^0\left(x+4\right)e^{3x}dx$
$00.2\cdot0.10000^2$
$\left(4-x\right)^{-0.5}$
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