$\left(2x-4\right)^4$
$\frac{8x^4+x^2-6x}{2x-4}$
$2\frac{dy}{dx}-4xy=x$
$75+99$
$\frac{3x^3-8x^2+6x+8}{x+4}$
$4x+6y=-3$
$\left(8-11-5\right)-\left(12-13\right)-\left(11+4\right)$
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