$w=\frac{\sin\left(x\right)^4-\cos\left(x\right)^3+1}{1+\cot^2x}$
$1\sqrt[5]{1}$
$\frac{a^6b^3c^3+1}{a^2bc-1}$
$y^66y^2+8$
$2w^2+2w-4$
$-4x\:x\:5x^2$
$\left(2x-5y+2x\right)dx+\left(1-6y-5x\right)dy=0$
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