$\frac{5}{6}x\frac{2}{3}$
$a^2\:-\:12a^2\:-88$
$\frac{x^2-4x+4}{x^2-x-2}$
$\lim_{x\to\infty}\:\left(1\right)^x-1$
$\left|6-12\right|-\left|-4\right|$
$\left(\sqrt[10]{x}.\sqrt[35]{x^2}\right)$
$5x^3-3x^26x$
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