$\frac{\left(x^2y^3\right)^3\left(xy^4\right)^{-3}}{x^2y}$
$2,26\cdot360$
$y=\frac{\left(3x^2+2\right)^2}{\left(x+2\right)^2\left(4x+3\right)}$
$\left(6a^3-2b^5\right)^3$
$\int\left(t^2-cos\:t\right)dt$
$10^3\:.\:\:8^3$
$x^2-12x+29=-3$
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