$0.2\cdot\frac{\left(6.24\cdot10^{18}\right)}{6.24\cdot10^{18}}$
$\int\frac{\left(1+lnx\right)^2}{x}dx$
$1x\left(4+3y\right)$
$\int\frac{3x+1}{\left(x^2+2\right)\left(x-3\right)}dx$
$\int4x^2\sqrt{1-3x^3}dx$
$\left(x^3-15\right)\left(x^3+32\right)$
$x^2-18x-4=0$
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