$\lim_{x\to-8}\left(\frac{x-9}{x^2\left(x+8\right)}\right)$
$\int_0^{\infty}\left(\frac{-1}{\left(x+1\right)^{\frac{1}{3}}}\right)dx$
$4+5\cdot6-4+8.2$
$2x^2-11x-6$
$-\left(-123+13\right)-125+145$
$\frac{dx}{dt}=\frac{te^t}{x\sqrt{1+x}}$
$\left(9^8\right)^0$
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