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Exercise

$-\frac{\ln\left(x\right)}{x^2}+\frac{1}{x^2}$

Step-by-step Solution

1

Appliquer la formule : $\frac{a}{b}+\frac{c}{b}$$=\frac{a+c}{b}$, où $a=-\ln\left(x\right)$, $b=x^2$ et $c=1$

$\frac{-\ln\left(x\right)+1}{x^2}$

Final answer to the exercise

$\frac{-\ln\left(x\right)+1}{x^2}$

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