$\frac{3}{\frac{3}{0}}$
$3x+1\:entre\:2x-4$
$\int_{.2}^1\left(3x^2+2\right)dx$
$a^5+a^2b^2$
$\frac{dy}{dx}=\frac{\left(1-x^2\right)}{xy}$
$\frac{4x^3-2x^2}{2x}$
$\left(x^2-2y^2\right)y^'+2xy=0$
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