$4x^2+8x$
$\csc\left(x\right)=3,1$
$4x+10<-2x-8$
$\frac{\sqrt{1-1}}{1-1}$
$200\frac{dy}{dx}+\frac{1}{0.0001}=10$
$\int\left(2^{2x}\cdot5x\right)$
$- 1 - [ - 3 - 2 + ( - 4 ) ]$
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