$4\sin\left(x\right)^2+8\sin\left(\frac{1}{2}\right)x\cdot\cos\left(\frac{1}{2}\right)x-2$

$5x+4+3x$

$0.375+0.2$

$\lim_{x\to\infty}\left(\frac{x^2+1}{x^2-2}\right)^{x^2}$

$\:h\left(x\right)=\:\left[\frac{cosx}{1+sinx}\right]4$

$\int\left(x-2x^2\right)^3\left(1-4x\right)dx$

$1-2+3+4+5-6+7-8$