$\left(2m+y\right)^5$
$\frac{2}{x^2-1}=\frac{1}{x-1}$
$\frac{-12a^3b^4}{6a^3b^4}$
$16a^4+40a^2b^3+25b^6$
$\frac{7^4}{7^{-2}}$
$\log\left(2x\right)=\log\left(10\right)$
$\left(45+65+78+98+12+32+25\right)-\left(-4-5-6-7-9-1\right)$
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