$\int\tan^25x-4\:dx$
$\frac{8x^3}{10x^5}$
$\:\frac{x+3}{2}+\frac{x-1}{4}>\:2$
$2x^3-5x^2-3x+\sqrt{16}-\sqrt[3]{-8}$
$x\cos\left(x\right)=3\cos\left(x\right)$
$3x-4<3x+4$
$7+x=17$
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