$\left(4m^2-10m+25\right)$
$\frac{\csc x}{1-\cos\left(x\right)}=\frac{1+\cos\left(x\right)}{\sin^3\left(x\right)}$
$36x^5+60x^3-48x^4$
$\int\left(x^2+5\right)^32dx$
$\frac{x^3-x-1}{x+1}$
$-5x=-35$
$x^2+157x-60$
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