$\sqrt[3]{1-\left(0\right)^2}$
$64\cdot22$
$\int_2^{\infty}\left(\frac{1}{\left(\sqrt{1+x^2}\right)}\right)dx$
$3000-365.80$
$\left(1\right)-\left(-5\right)$
$x^2-3x-28\ge0$
$\lim_{x\to-\infty}\left(x^{2}-2x+1\right)$
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