$3+\frac{3}{5}_-\frac{1}{8}$
$z-9<1$
$4^2+\:-\left(18\right)\:+\:\left(-9\right)\:$
$\left(\frac{1}{2}x^2\right)^5$
$m^2+6m+9=0$
$\left(x+7\right)\left(x-7\right)=-3x$
$2x-3x-x$
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