$-5\left(7y+6\right)+5\le-8\left(8-4y\right)$
$2x-3\le3x+7$
$x^4y^{-3}$
$\lim_{x\to2}\left(\frac{x^2-3x-10}{x^2+x-6}\right)$
$\left(4x-9\right)\left(4x+12\right)$
$\frac{1}{\cos\left(\frac{3\pi}{8}\right)}$
$\frac{4.326}{3}$
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