$5a+20$
$\frac{d}{dx}xy^4+x^2y=\frac{d}{dx}x+3y$
$\left(sec^2x-1\right)csc^2x\:=\:sec^2x$
$\int\left(tlnt^2\right)dt$
$\left(3\right)\left(-22\right)$
$\left(-3+2\right)-\left(7-2\right)$
$\tan x=\frac{1}{\cot x}$
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