$\left(x-3\right)\left(3x+2\right)$
$-4\left(\frac{1}{4}\right)-3$
$-6-13+5-7+8+1-4-5+7$
$x^2-16x+4=0$
$\left(5a^2x-3by^3\right)^2$
$192a^2b-300a^2bc^4$
$\int\left(5x+3\right)^{-10}dx$
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