$\left(3+4ax\right)^2$
$\left(2n+3r\right)\left(2n+2r\right)$
$\left(2xy-4x^{2}z+1\right)\left(3xy^{2}+2xy+z\right)$
$9-12-\left(-7\right)+5+\left(-8\right)+1-\left(12\right)-18$
$-.75\:+0.2\:$
$\frac{dx}{dt}=\frac{1}{2x}$
$\int\frac{\sqrt{x}+3}{x}\cdot dx$
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