$\frac{x^2-9x+15}{x^2-5}$
$7,1 - 1,7$
$\lim_{x\to1}\left(\frac{15\left(\ln\left(x\right)-1\right)+15}{\left(x-1\right)\ln\left(x\right)}\right)$
$2\cdot7x\cdot6$
$5x^2-16x+3$
$( - 11 x ^ { 2 } + 3 x + 1 ) : ( x - 1 )$
$\frac{b^2}{b}$
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