$\sqrt[2]{5^2}$
$\frac{1}{2}+-3+0.3$
$4x^2-y^2=c$
$\sqrt[3]{b^4}$
$4cosec^2\left(2x\right)=sec^2\left(x\right)cosec^2\left(x\right)$
$\frac{x^3-15x-68}{x-4}$
$\lim_{x\to\infty}\left(\frac{e^{-x}}{ln\left(1+e^{-x}\right)}\right)$
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