$\sec^2x-1\left(x\right)^2=\frac{1}{\sin\left(x\right)^2\cdot\cos\left(x\right)^2}$
$\left(-\frac{7}{6}x^3\right)+\left(+2x^3\right)$
$\frac{2}{3}x=-12$
$6x^2-9x-27$
$\left(-76-\left[42+\left(12-6\right)+3\right]-10\right)-2$
$\left(d+a\right)^4$
$\left(3q+7\right)^{3\left\{\right\}}$
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