$\lim_{x\to\infty}\left(\frac{x}{x+18}\right)^x$
$b^2+\frac{3}{2}\left(b\right)$
$-10:-5$
$\lim_{x\to0}\left(\frac{x^2+3x+12}{-6ln\left(x^3\right)}\right)$
$\frac{x^{12}+64}{x^4-4}$
$\frac{30}{-3}$
$6x^2-15^2+21^2$
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