$6x^2+3x-5=0$
$8a+4b-12c$
$-13x-2\le-11x-15$
$\frac{d}{dx}+3x=2x+4y$
$7y-8^3$
$\frac{6}{\left(x+2\right)\left(x+3\right)}$
$sinxdx+4ycos^2xdy=0$
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