$4.\left(8+\right)\left(-30\right)$
$x+2<3x-8$
$\lim_{x\to0}\left(\frac{t\cdot sin\left(t\right)}{1-cos\left(t\right)}\right)$
$\frac{sin\left(\theta\:\right)}{sec\left(\theta\:\right)+1}$
$\left(z^5\right)\left(z\left(-3\right)\right)$
$3x^2-8x-8=0$
$-2xy+4xz$
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