$x^2+x^2-8=0$
$5x^2-47x+56=0$
$\int\left(-16x^3\left(-4x^4-1\right)^{-5}\right)dx$
$\frac{-6j^{-8}}{-2\left(j^{-3}\right)^5}$
$\int\frac{66}{\left(x-3\right)\left(x+5\right)}dx$
$25w^2+20w-4$
$-3x+4\ge0$
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