$a\left(a+c\right)+c\left(c+b\right)$
$xy'+y^2+y=0$
$7x^2-24x+6$
$\left(2x^2\:+\:1\right)\left(x-\frac{2}{x}\right)^4$
$7x^2+x-8$
$3x-2\le x-8$
$x^2+6x+9=1$
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