$a^2x^6-b^2y^4$
$\left(16x-7y\right)^2$
$\left(2a^8-5a^4\right)^2$
$\lim_{x,y\to0,1}\left(\frac{y}{x}\right)$
$\frac{dy}{dx}=2\left(\sec\left(x\right)\right)^2\left(y+3\right)$
$\frac{\sin\left(x\right)^4-\sin\left(x\right)^6}{cos\left(x\right)^4-\cos\left(x\right)^6}$
$=\frac{x^{2}-3}{x^{2}+2}$
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