$\frac{4x^2-8x+4}{2x+1}$
$\int3tan\left(2x\:-\:6\right)dx$
$20y^22$
$\left(10\right)-\left(-8\right)$
$\left[\left(6^2\right)^3\right]^2$
$\left(4x+3\right)\left(2x+7\right)$
$\left(8x.-5\right)^2$
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