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Exercise

$\sqrt{a^6+b^6+2};\:a^4+b^4=47\:;\:\left(a\right)\left(b\right)=1$

Step-by-step Solution

1

Calculate the numerical value for $\sqrt{a^6+b^6+2}$ when $a^4+b^4=47$ and $ab=1$. Replace the unknowns with their corresponding values

$\sqrt{a^6+b^6+2}$

Final answer to the exercise

$\sqrt{a^6+b^6+2}$

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