$\log\left(2\right)+\log\left(x-5\right)=1$
$3x-12-6+\frac{1}{3}x+2$
$\lim_{x\to0}\left(\frac{\ln\left(x\right)}{x^3-3x+2}\right)$
$128.3-41.970$
$-\left(9-5+12\right)+16-3$
$2b+4a-2a^2+b^2;\:a=7;\:b=6$
$\frac{81x^5}{9x^5}$
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