$4^{-2}n^{-4}y^3$
$\left(\frac{dx}{dt}=y\right)\left(\frac{dy}{dt}=4x\right)$
$\int_0^{\frac{1}{3}}\left(\frac{4}{1+9x^2}\right)dx$
$\left(3xy-4mn9\right)^2$
$\left(3x-2\right)+\left(x+8\right)\cdot\left(2x+9\right)$
$95\cdot5$
$40-0.0834$
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