$7-3x<2-4x$
$\left(\frac{2}{5}x^3+\frac{1}{4}y^2\right)^2$
$2x^2-4x+5=6$
$s^2+4s+1$
$a^4+a^3-2a^2$
$3\frac{dy}{dx}=\frac{e^ysin^2\left(x\right)}{y\:sec\left(x\right)}$
$\frac{3t^2}{\sqrt[5]{t^2}}-\frac{7t^{-1}}{\sqrt{t^3}}+8\sqrt[7]{t^3}+4t^{-3}-6$
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