$x^3dy+y^4dx=0$
$\frac{dy}{dx}=\left(y-3\right)\left(y-5\right)$
$\left(\frac{4-8x}{2}\right)>2$
$\frac{1}{25}a^6+4a^2$
$-135\:+\:-693\:=\:$
$3\int m^4\left(5m^3-3m+8\right)dm$
$x^2<60$
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