$\left(3a-4b^3\right)\left(3a+4b^3\right)$
$20\cdot\left(-3\right)^2$
$\frac{2}{x+1}<-3$
$\frac{\left(6x^3-9x^2+18x\right)}{3x}$
$1714+1500+1636+461+500$
$\frac{x}{\left(x^2+2\right)^{\frac{1}{2}}}$
$x\sqrt{28y^2}$
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