$\frac{\sin^3\left(x\right).\cos\left(3x\right)+\cos^3\left(x\right).\sin\left(3x\right)}{\sin\left(4x\right)}$
$17g^2-2g^2$
$\frac{9}{3}+4$
$\left(x^2+8\right)\left(x^2+7\right)$
$\frac{-16^2}{n}$
$f\left(x\right)=6x^3+5x^2+x$
$3x+6\ge2x+12.xeq$
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