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Find the derivative of $\sqrt{3a^2}b^3\sqrt{6a^5}b$

Step-by-step Solution

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Final Answer

$12\sqrt{2}\sqrt{a^{7}}b^{3}+\frac{21\sqrt{2}}{2}b^{4}\sqrt{a^{5}}$
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Step-by-step Solution

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Simplifying

$\frac{d}{db}\left(b^{4}\sqrt{3a^2}\sqrt{6a^5}\right)$

Learn how to solve implicit differentiation problems step by step online.

$\frac{d}{db}\left(b^{4}\sqrt{3a^2}\sqrt{6a^5}\right)$

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Learn how to solve implicit differentiation problems step by step online. Find the derivative of (3a^2)^1/2b^3(6a^5)^1/2b. Simplifying. Apply the product rule for differentiation: (f\cdot g)'=f'\cdot g+f\cdot g', where f=b^{4} and g=\sqrt{3a^2}\sqrt{6a^5}. Apply the product rule for differentiation: (f\cdot g)'=f'\cdot g+f\cdot g', where f=\sqrt{3a^2} and g=\sqrt{6a^5}. The power of a product is equal to the product of it's factors raised to the same power.

Final Answer

$12\sqrt{2}\sqrt{a^{7}}b^{3}+\frac{21\sqrt{2}}{2}b^{4}\sqrt{a^{5}}$

Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

Find the derivativeFind derivative of 3a^2^0.5b^3 using the product ruleFind derivative of 3a^2^0.5b^3 using the quotient ruleFind derivative of 3a^2^0.5b^3 using logarithmic differentiationFind derivative of 3a^2^0.5b^3 using the definition

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Function Plot

Plotting: $12\sqrt{2}\sqrt{a^{7}}b^{3}+\frac{21\sqrt{2}}{2}b^{4}\sqrt{a^{5}}$

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0
a
b
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d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
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×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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Main Topic: Implicit Differentiation

Implicit differentiation makes use of the chain rule to differentiate implicitly defined functions. For differentiating an implicit function y(x), defined by an equation R(x, y) = 0, it is not generally possible to solve it explicitly for y(x) and then differentiate. Instead, one can differentiate R(x, y) with respect to x and y and then solve a linear equation in dy/dx for getting explicitly the derivative in terms of x and y.

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