$13^3\:times\:13^7$

$\csc^2\left(x\right)\tan^2\left(x\right)-1=\tan\left(x\right)$

$-\frac{1}{3}x\:+\frac{1}{2}y\:+\frac{3}{8}-3y+2x-\frac{1}{6}y-\frac{3}{4}x-\frac{1}{2}$

$\frac{16.750}{12500}$

$-2+\left(-3\right)+4-\left(-3\right)-5$

$f\left(x\right)=\tan\left(\frac{4}{3}x^3-\frac{4}{5}x^2\right)$

$\frac{x^3+4}{x+4}$