$h\left(x\right)=in\left(x^2+13x-5\right)$

$\int\left(\frac{2}{x\left(3x-8\right)}\right)dx$

$\frac{1}{\csc^2\left(x\right)}+\frac{1}{\sec^2\left(x\right)}=1-\tan^2\left(x\right)$

$4006-1820$

$z^8+12z^1+144$

$\lim_{x\to-3}\left(\frac{x+2}{\sqrt{x+3}-1}\right)$

$4x^2+9x^2+12xy$