$\frac{dy}{dx}x^2y^2=e^{\ln\left(xy\right)}$
$\lim_{x\to\infty}\left(\frac{\arctan\left(x\right)}{x}\right)$
$\frac{dy}{dx}\left(xy-4x=y^2\right)$
$\left(4x-8\right)^3$
$\frac{3x^3+2x^27x+2}{x+2}$
$y'=\:y^2-4$
$24-\left(-18\right)$
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