$e^{x+3y}dy=xdx$
$dy=-2\left(x^2+3x\right)dx$
$\int\frac{1}{5}x^5-\sqrt{x}+\frac{4}{3x}-\frac{2}{x^2}\:dx$
$\lim_{x\to\infty}\left(\frac{e^{-x^2}}{x^{-3}}\right)$
$\left(\frac{1}{2}x^2-6y^3\right)^5$
$\frac{\left(2n^2\right)^2}{n^4.2n}$
$6^2+3x+1\:entre\:x-1$
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