$\int\:\frac{2x}{\sqrt{x^2-9}}dx$
$16y^2+8y=0$
$\int\left(-2x^2-7x^3+5x^2-4x-3\right)dx$
$\frac{x^3+x^2-x-3}{x^2-3}$
$3\left(1-2x\right)\le0$
$\frac{x^2-6x+1}{x-1}$
$12x^2+14x-2=8$
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