$\frac{x+8}{2}=x-10$
$x^r\left(2r^2+3r+1\right)=0$
$\left(-2m^2n^3\right)^4\left(3mn^4\right)^2$
$f\left(x\right)=\sqrt{5x^2}-2x+8$
$-3\left(m-2\right)$
$-4+\left(3\right)\left(-8\right)+7$
$\left(a^2+8p\right)\left(a^2-8p\right)$
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