$2x+1>-3\left(x-2\right)\:$
$\frac{x^3-7x^2+8x-2}{x-1}$
$\sec^4\left(z\right)-2\sec^2\left(z\right)+1$
$\sqrt[3]{\frac{-64}{-8}}$
$\frac{d}{dx}3y-x^2=y^2$
$-12+11-9-9-15$
$-x^2=-x-6$
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