$16x^4\:-\:256$
$\left(3a^3+8b^4\right)^4$
$-2x-3+x-1$
$\lim_{x\to-\infty}\left(\frac{e^{6x}}{x^{-2}}\right)$
$\frac{2x^5-4x^4+8x+6}{2x-1}$
$+8:8+2$
$\int\frac{\sqrt{y^2-49}}{y}dx$
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