$\left(x-5\right)-2\left(3x-4\right)$
$3\:x\:\left(x^2-3x\right)+5x$
$4x^{\frac{5}{3}}-\frac{x^{\frac{5}{3}}}{2}$
$\frac{2e^{2x}+3}{8}$
$\frac{dx}{dt}=\frac{36t^2}{x}$
$5\left(x-3\right)=5\left(4x+3\right)$
$\int x\left(u^{\frac{3}{2}}-3u+14\right)du$
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