$x^2+2x-12$

$10+2\left(4\right)-3\left(5\right)$

$\frac{1}{\cos\left(x\right)}-\frac{\cos\left(x\right)}{1+\sin\left(x\right)}=\tan\left(x\right)d$

$-3c\:-\:2\:\left(2\:-\:4c\right)=51$

$4x^2-y^2-8x+8=0$

$\left(\frac{x^2}{y}\right)^{-3}$

$\frac{dx}{dt}=1-1x,\:x\left(0\right)$