$x^2y'=2xy+3$
$\left(2x^3+x^2-5x+3\right)\left(3x^2+5x-3\right)$
$\left(tan\:x-1\right)^2$
$y'=-3x^2y$
$8-2^x=0$
$\left(a\:-\:b\:+\:2c\right)^3$
$3.14\cdot8.5^2$
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